4n^2-63=-4n

Solution for 4n^2-63=-4n equation:

4n^2-63=-4n

We move all terms to the left:

4n^2-63-(-4n)=0

We get rid of parentheses

4n^2+4n-63=0

a = 4; b = 4; c = -63;
Δ = b2-4ac
Δ = 42-4·4·(-63)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-32}{2*4}=\frac{-36}{8}
=-4+1/2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+32}{2*4}=\frac{28}{8}
=3+1/2
$